C++ Institute CPA-21-02 - Questions & Answers

What happens when you attempt to compile and run the following code?

#include <iostream>

using namespace std;

void set(struct person*);

struct person

{

int age;

};

int main()

{

struct person e = {18};

set(&e);

cout<< e.age;

return 0;

}

void set(struct person *p)

{

p?>age = p?>age + 1;

}

What happens when you attempt to compile and run the following code?

#include <iostream>

using namespace std;

int main()

{

int x=2, *y, z=3;

y = &z;

cout<<x**y*x***y;

return 0;

}

What is the output of the program?

#include <iostream>

using namespace std;

int main()

{

int tab[4]={10,20,30,40};

tab[1]=10;

int *p;

p=&tab[0];

cout<<*p;

return 0;

}

What happens when you attempt to compile and run the following code?

#include <iostream>
#include <string>
using namespace std;
class A {
int x;

protected:
int y;
public:
int z;
A() { x=1; y=2; z=3; }
};
class B : public A {
string z;
public:
void set() {
y = 4;
z = "John";
}
void Print() {
cout << y << z;
}
};
int main () {
B b;
b.set();
b.Print();
return 0;
}

What happens when you attempt to compile and run the following code?

#include <iostream>
#include <string>
using namespace std;
class A {
public:
int x;
A() { x=0;}
};
class B {
public:
int x;
B() { x=1;}
};
class C :public A, public B {
public:
int x;
C(int x) {
this?>x = x;
A :x = x + 1;
}
void Print() { cout << x << A::x << B::x; }
};
int main () {
C c2(1);
c2.Print();

return 0;
}

What happens when you attempt to compile and run the following code?

#include <iostream>
using namespace std;
int main (int argc, const char * argv[])
{
int x,y;
union t
{
char tab[2];
int i;
};
union t u;
u.tab[0] = 1;
u.tab[1] = 2;
u.i = 0;
x = u.tab[0];
y = u.tab[1];
cout << x << "," << y << "," << u.i;
return 0;
}

What happens when you attempt to compile and run the following code?

#include <iostream>

using namespace std;

int main()

{

int x=2, *y;

y = &x;

cout << *y + x;

return 0;

}

What happens when you attempt to compile and run the following code?

#include <iostream>

using namespace std;

int main()

{

int x=0;

int *ptr;

ptr = &x;

cout<<x<<" "<<*ptr;

return 0;

}

What happens when you attempt to compile and run the following code?

#include <iostream>

#include <string>

using namespace std;

class First

{

string *s;

public:

First() { s = new string("Text");}

~First() { delete s;}

void Print(){ cout<<*s;}

};

int main()

{

First FirstObject;
FirstObject.~First();

}